If 0.8000 g of a mineral yields 0.2400 g of NaCl + KCl, and this mixture contains 58.00% of Cl, what is the percentage of Na2O and K2O in the mineral?
To Raphael, Ariel, Maxine, et al.: this is not a place to dump all of your homework. I've worked SEVERAL of these problems below. I shall be happy to help you through the others AFTER you show some of your work. Alternatively, explain what you don't understand about the question and what you do understand about the question. Again, let me remind you that it takes more time to answer these when you change screen names.
To find the percentage of Na2O and K2O in the mineral, we need to calculate the amount of Na2O and K2O present in the mixture.
Given:
Mass of mineral = 0.8000 g
Mass of NaCl + KCl = 0.2400 g
To calculate the percentage of Cl in the mixture, we can use the formula:
% Cl = (mass of Cl / mass of mixture) * 100
% Cl = (mass of NaCl + KCl / mass of mixture) * 100
% Cl = (0.2400 g / 0.8000 g) * 100
% Cl = 30.00%
Since we know that the mixture contains 58.00% of Cl, we can calculate the percentage of Na2O and K2O as follows:
% (Na2O + K2O) = 100% - % Cl
% (Na2O + K2O) = 100% - 30.00%
% (Na2O + K2O) = 70.00%
Therefore, the percentage of Na2O and K2O in the mineral is 70.00%.