Question

x^2-7x+10=28

Answer 1

First you need to set the equation to zero so x^2 -7x +10-28 = 0

10-28 = -18
x^2 -7x -8 = 0
To factor you ned the factors of c that add to b because a = 1
factors of -18 that add to -7 are (-9) and (+2)
so (x-7)=0and(x+2)= 0 so x=7 and x = -2