Posted by lyan on Monday, January 16, 2012 at 4:44pm.
Write the equation and balance it.
2a. Convert 20.0 g C3H8 to moles.
2b. Convert 20.0 g O2 to moles.
3a. Using the coefficients in the balanced equation, convert moles C3H8 to moles H2O.
3b. Same procedure convert moles O2 to moles H2O.
3c. You have two different answers and both can't be right. The correct answer in limiting reagent problems is ALWAYS the smaller number and the reagent producing that number is the limiting reagent.
4. Using the smaller number, convert moles to grams. g = moles x molar mass.
To calculate grams excess reagent remaining, use step 3a or 3b above to convert moles of the non-limiting reagent to moles of limiting reagent, convert to grams, and subtract from 20.0.
Related Questions
Chemistry - The combustion of 132 g of propane, C3H8, with excess oxygen ...
Chemistry - Consider the combustion of propane (C3H8) in the presence of oxygen...
chem - Consider the combustion of propane (C3H8) in the presence of oxygen: C3H8...
chemistry (combustion and heat) - How much heat is evolved when 5.00g of propane...
CHEM - Many home barbeques are fueled with propane gas C3H8. What mass of carbon...
Chemistry - Propane, C3H8, is a common fuel gas. Use the following to calculate...
Chemistry - Consider the combustion of propane: C3H8(g)+5O2(g) yields 3CO2(g) + ...
Science - Consider the combustion of propane: C3H8(g)+5O2(g) yields 3CO2(g) + ...
chemistry - what mass of oxygen would be required to completely burn 6.75 g of ...
chemistry - The combustion of propane (C3H8)produces CO2 and H20: C3H8(g)+5O2(g...
For Further Reading
