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December 18, 2014

December 18, 2014

Posted by **Molly** on Monday, January 16, 2012 at 3:29pm.

sin t, cos t; quadrant 2

- pre-calculus -
**Damon**, Monday, January 16, 2012 at 3:39pmsin^2 t = 1 - cos^2 t

sin t = +/- sqrt (1-cos^2 t)

in quadrant 2, sin t is + so use + sign

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