Posted by amanda and leah on Monday, January 16, 2012 at 11:58am.
Use g and the height of the table (H) to get the time that it takes the block and bullet to fall.
t = sqrt(2H/g)= 0.429 s
Then divide 1.7 m by that time to get the (horizontal) velocity of the block/bullet right after impact. Call it v. That horizontal velocity component remains constant as it falls.
Once you have the velocity after impact, use conservation of momentum to get the bullet velocity, V.
m V = (m + M)*v
V = (m + M)*v/m
Related Questions
college physics - An 7.81g bullet is fired into a 220g block that is initially ...
physics - An 8.82g bullet is fired into a 235g block that is initially at rest ...
physics!! - An 8.82g bullet is fired into a 235g block that is initially at rest...
physics - An 8.00 g bullet is fired into a 160 g block that is initially at rest...
physics - An 8.00 g bullet is fired into a 160 g block that is initially at rest...
physics - An m1 = 8.40 g bullet is fired into a m2 = 2.17 kg block that is ...
physics - An 8.00 g bullet is fired into a 250 g block that is initially at rest...
physics - An 8.00 g bullet is fired into a 160 g block that is initially at rest...
physics - An 8.00 g bullet is fired into a 180 g block that is initially at rest...
college physics - a bullet of mass 8g is fired into a block of mass 260g that is...
For Further Reading