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March 5, 2015

March 5, 2015

Posted by **Saurav** on Monday, January 16, 2012 at 11:46am.

- Maths -
**Steve**, Monday, January 16, 2012 at 12:30pmdraw a diagram. Let the height of the tower be h, and the length of shadow for a 60deg sun be x. Then we have

h/x = √3

h/(x+40) = 1/√3

√3 x = (x+40)/√3

3x = x+40

x = 20

h = 20√3 = 34.64m

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