Posted by **Kitty** on Monday, January 16, 2012 at 11:24am.

Jack drives 6.45 km to work and his car gets about 0.0147 km per gram of gasoline. Using the balanced chemical equation (you need to find out this equation by yourself), how many grams of CO2 is produced in this trip to work

- Chemistry -
**Steve**, Monday, January 16, 2012 at 12:18pm
Gasoline can be represented by octane C8H18. Its combustion, in the most straight-forward sense is to carbon dioxide and water.

2C8H18 + 25O2 ~> 16CO2 + 18H2O

so, he needs 6.45km / .0147km/g = 438.7755g of gas. That assumes complete combustion, of course.

mole weight is about 12*8 + 18*1 = 114g/mole

438.7755g / 114g/mole = 3.849 moles of gasoline

each mole of gasoline produces 8 moles of CO2, so we end up with 30.791 moles, or 30.791*(12+2*16) = 1354.8g of CO2.

- Chemistry -
**Kitty**, Monday, January 16, 2012 at 12:40pm
Thank you so much!

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