Posted by **Bobby** on Sunday, January 15, 2012 at 9:15pm.

A 45 kg cart is moving across a frictionless floor at 1.7 m/s. A 60 kg boy, riding in the cart, jumps off the cart so that he hits the floor moving forwards in the initial direction of the cart's motion with a velocity of 2.8 m/s. What is the velocity of the cart after the boy jumped?

- Physics -
**Damon**, Sunday, January 15, 2012 at 9:17pm
initial mass = 45 + 60 = 105 kg

initial momentum = 105 * 1.7 = final momentum

so

105*1.7 = 2.8*60 + 45 v

- Physics -
**Bobby**, Sunday, January 15, 2012 at 9:29pm
but how do you go from 105*1.7 = 2.8*60 + 45 v to the answer?? i'm so confused!

- Physics -
**bobpursley**, Sunday, January 15, 2012 at 9:36pm
This is pretty basic algebra.

subtract 2.8*60 from each side. Then divide both sides by 45.

## Answer This Question

## Related Questions

- physics - A 48 kg cart is moving across a frictionless floor at 3.3 m/s. A 50 kg...
- physics - A 50. kg cart is moving across a frictionless floor at 2.0 m/s. A 70. ...
- physics - A 50. kg cart is moving across a frictionless floor at 2.0 m/s. A 70. ...
- PHYSICS - A Few questions- please help!!! also show steps! What magnitude of ...
- Physics - A 50 kg boy runs at a speed of 10 m/s and jumps onto a cart. The cart ...
- physics - A full shopping cart requires a force of 88.0 Newtons to move across a...
- Physics - A cart on an airtrack is moving at 0.5m/s.when the air is suddenly ...
- Physics - Two boys standing on carts that move along a horizontal frictionless ...
- Physics 1 - A cart with mass 340 g moving on a frictionless linear air track at ...
- physics - A 10.0 kg cart and a 15 kg cart are locked together with a compressed ...

More Related Questions