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Posted by on Sunday, January 15, 2012 at 11:57am.

Two point charges are 10.0 cm apart and have charges of 2.0 μC and –2.0 μC, respectively. What is the magnitude of the electric field at the midpoint between the two charges?

8.99*10^9(2*10^-6/.025)=719200

Two equal charges are separated by 3.7 x 10-10 m. The force between the charges has a magnitude of 2.37 x 10-3 N. What is the magnitude of q on the charges?

1.9x10^-16 (I got this using Coulomb's Law and working backward)

Thanks in advance!

  • Science - , Sunday, January 15, 2012 at 12:13pm

    Your first number is the E-field due to each charge. You have to double it, since they are both in the same direction.

    For the second case,

    8.99*10^9*q^2/(3.7*10^-10)^2 = 2.37*10^-3

    q^2 = 3.61*10^032 C^2

    q = 1.90*10^-16 C
    I agree with your answer.

  • Science - , Sunday, January 15, 2012 at 7:43pm

    Great! Thank you!

  • Science - , Sunday, January 15, 2012 at 8:23pm

    Wait, can you please explain the first answer? What am I supposed to double? And after I double it, do I do what I did originally?

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