Posted by **rei** on Saturday, January 14, 2012 at 9:25pm.

A 0.280 kg block on a vertical spring with a spring constant of 4.12 × 10^

3 N/m is pushed downward, compressing the spring 0.0600 m.

When released, the block leaves the spring and travels upward vertically.

The acceleration of gravity is 9.81 m/s^

2. How high does it rise above the point of release?

Answer in units of m

- physics - Energy -
**rei**, Saturday, January 14, 2012 at 9:52pm
Just giving the equation to solve the problem would be nice too!

- physics - Energy -
**drwls**, Sunday, January 15, 2012 at 6:17am
The potential energy of the compressed spring at release equals the potential energy gained at the maximum distance above the release point. Let that distnce be X and the initial spring compression be d = 0.06 m

(1/2) k d^2 = m g X

k is the spring constant, which you know is 4120 N/m.

m = 0.28 kg

Solve for X

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