Chemistry
posted by Hannah on .
According to the ideal gas law a 9.03 sample of oxygen gas in a 0.8112 container at 499k should exert a pressure of 456atm. By what % does the pressure calculated using van der waals equation differ from the ideal pressure?
For O2 gas a=1.36 L^2atm/mol2 and b=3.18e2
Hint: %diff= 100 X (P ideal  P van der waal) / P ideal
I know that van der waals equation is
(P + a [n/v]^2) (vbn) = nRT but I have no idea how to use this and my textbook does not give any examples. Thank you for your help!

First, you omitted the units on the 9.03 WHAT in a 0.8112 WHAT container. I'm confused because you are confused. There is nothing here that you need an idea about. You have a and b, R, T, and n. Solve for P by van d equation, then use the usual PV = nRT and solve for P. Then follow the hint in the problem which tells you how to solve for the % difference.