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March 4, 2015

March 4, 2015

Posted by **Sara** on Saturday, January 14, 2012 at 12:51pm.

- precalculus -
**Reiny**, Saturday, January 14, 2012 at 5:21pmf(x) or y = 4-2ln(x+1)

domain: x > -1

range : y is any real number

asymptote: x = -1

for the inverse:

interchange x and y variables

x = 4 - 2ln(y+1)

2ln(y+1) = 4-x

ln (y+1) = (4-x)/2

y+1 = e^((4-x)/2)

y = e^((4-x)/2) - 1

domain: x is any real number

range y > -1

asymptote : y = -1

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