What will be the magnitude of work if a force of 25N pulls a stone through distance of 5m in its direction ?

w= f.d

w= 25*5= 125 j

125

125 is definitely

To determine the magnitude of work in this scenario, you can use the formula:

Work = Force × Distance × Cos(θ)

Where:
- Work is the magnitude of work done (in joules, J)
- Force is the applied force (in newtons, N)
- Distance is the displacement of the object (in meters, m)
- θ (theta) is the angle between the force vector and the displacement vector (in degrees)

In this case, the force and displacement are in the same direction, so the angle between them is 0 degrees. Therefore, Cos(0) = 1.

Now you can substitute the given values into the formula:

Work = 25N × 5m × Cos(0)

Since Cos(0) = 1, the equation becomes:

Work = 25N × 5m × 1

Calculating the multiplication:

Work = 125N × m

As a result, the magnitude of work in this scenario would be 125 joules (J).

W=Fs

W=25N * 5m = 1255J

25 * 5 = 1255 Joules