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January 31, 2015

January 31, 2015

Posted by **95** on Saturday, January 14, 2012 at 1:20am.

- precalc -
**drwls**, Saturday, January 14, 2012 at 1:37amThat is not an ellipse. You cannot have x^2 and y^2 terms of opposite sign, for an ellipse.

You have a hyperbola. Complete the squares for standard form.

- precalc -
**95**, Saturday, January 14, 2012 at 1:54amokay, Thank you very much:)

- precalc -
**95**, Saturday, January 14, 2012 at 2:08amwait, I still end up with the wrong answer. I end up with

4(x-5)^2/-120 - 9(y+2)^2=-120

9 can't go into -120

My procedure:

(4x^2-40x)-(9y^2+36y)=-100

4(x^2-10x +4)-9(y^2 +4 +4)=-100+ 4(4)-9(4)

4(x-5)^2-9(y+2)^2=-120

(x-5)^2/-30 - ? 9 can't go into -120 evenly

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