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Posted by on Saturday, January 14, 2012 at 1:20am.

Write the equation of the ellipse in standard form: 4x^2-9y^2-40x+36y+100=0

  • precalc - , Saturday, January 14, 2012 at 1:37am

    That is not an ellipse. You cannot have x^2 and y^2 terms of opposite sign, for an ellipse.

    You have a hyperbola. Complete the squares for standard form.

  • precalc - , Saturday, January 14, 2012 at 1:54am

    okay, Thank you very much:)

  • precalc - , Saturday, January 14, 2012 at 2:08am

    wait, I still end up with the wrong answer. I end up with
    4(x-5)^2/-120 - 9(y+2)^2=-120

    9 can't go into -120

    My procedure:
    (4x^2-40x)-(9y^2+36y)=-100
    4(x^2-10x +4)-9(y^2 +4 +4)=-100+ 4(4)-9(4)
    4(x-5)^2-9(y+2)^2=-120
    (x-5)^2/-30 - ? 9 can't go into -120 evenly

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