Chemistry
posted by Hannah .
A 12.0L sample of a as at a constant pressure of 608 mm Hg was heated from 40 degrees celsius to 60 degrees celsius. What volume does the gas now occupy?
would I multiply 608 by 12 and then divide by the degrees celsius?

I wonuldn't do that.
Charles law:
V1/V2= T1/T2 temps in kelvins 
So would I set it up as 12.0L / v2 = 313 K / 333K ?

I got 11.3 L as my answer. Is this correct?

The set up looks ok to me but if T goes up doesn't V go up? Your calculation is lower?

I tried again and got 12.8

I'll buy that.

Well the answer choices were 18L, 8.0L, 12.8L, 15L and 11.3L and when i divided 12 by 0.9399 which I got from 313/333 I got 12.76.

And I got 12.76 also BUT you have three significant figures in 12.0, 313 and 333 so you may have 3 in the answer (not 4); therefore, round 12.76 to 12.8.

ok thank you