Posted by **Anonymous** on Friday, January 13, 2012 at 8:08pm.

One side of a triangle is x inches longer than another side. The ray bisecting the angle formed by these sides divides the opposite side into 3- inch and 5-inch segments. Find the perimeter of the triangle in terms of x.

- Geometry -
**bobpursley**, Friday, January 13, 2012 at 9:07pm
http://en.wikipedia.org/wiki/Angle_bisector_theorem

Then S/(S-x)= 5/3

and 3X=5S-5X

or 5x=3S or x=3s/5 or S=5x/3

Perimeter: (3+5)+ S+(S-x)=

8+2*5x/3 -x=

8+x(10/3-1) and you can surely simplify that.

check my thinking

- Geometry -
**Reiny**, Friday, January 13, 2012 at 10:45pm
Thought this question looked familiar, so I went back to find it and found your objection to my solution

http://www.jiskha.com/display.cgi?id=1326173456

Of course you were right to spot my error, it should have said

1.5x + 1.5x + x + 8

= 4x+8

Also just noticed a typo in bobpursley's solution

2nd line should have been

3S = 5S - 5X , then

5x = 2s

s = 5x/2 or 2.5x

perimeter = 8 + s + s-x

= 8 + 5x-x = 4x+8

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