Posted by **Sienna** on Friday, January 13, 2012 at 3:28pm.

A shopkeeper packages together two types of hard candy: peppermint and cinnamon. Seperately the peppermint candy sell for $1.80/kg and the cinnamon candy sells for $2.40/kg. The mixture sells for $2.16/kg. Determine the amount of each type of candy that is required to make 50kg of the mixture. Verify your answer.

-Determine a linear equation to represent the total mass of the new mixture.

-Determine a linear equation to represent the cost of the new mixture.

-Apply a process to verify the point of intersection

- Math -
**Steve**, Saturday, January 14, 2012 at 12:02am
we have p kg of peppermint and c kg of cinnamon

p+c=50, so c = 50-p

the price of all the peppermint + the price of the cinnamon is the price of all the mixed bags.

1.80p + 2.4(50-p) = 2.16(50)

1.80p + 120 - 2.4p = 108

.60p = 12

p = 20

so,

c = 30

## Answer This Question

## Related Questions

- Analytic Geometry(Math) - A shopkeeper packages together two types of hard candy...
- Math - Robin and Emily are selling boxes of candy bars. Robin sells 36 boxes of ...
- 5th grade algebra word problem - Ron made cookies for the fair. His sister made ...
- Math - Robin and Emily are selling boxes of candy bars. Robin sells 36 boxes of ...
- Algebra - For the fundraiser, will sold 225 candy bars.he earns $1 for each ...
- Math Counting - A bowl of candy contains many pieces of candy but only six ...
- Math - Chester and Kelsey were given a box of candy to sell. Each box of candy ...
- math - Moffett’s Candy Factory makes candy in the shape of cylinders. The net ...
- math word problems. - The candy factory sells three times as many mints as it ...
- English - 1. Where is there a candy striper? 2. Where can we see a candy striper...

More Related Questions