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April 18, 2014

April 18, 2014

Posted by **smith lionel** on Friday, January 13, 2012 at 11:55am.

- calculus -
**Steve**, Friday, January 13, 2012 at 1:00pmMVT states that for an interval [a,b] there is a c such that f'(c) = (f(b)-f(a))/(b-a)

Here letting f(x) be distance at time x minutes,

f(0) = 0

f(5) = 4

(f(5)-f(0))/(5-0) = 4/5 mi/min (that's 48 mph)

MVT states that at some 0<= c <= 5, f'(x) = 4/5

f'(x) is the speedometer reading at x minutes.

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