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compute the least acceleration with which a man of mass 75 kg can slide down a rope which can sustain a weight of 580 N

  • physics -

    You really mean the minimum deceleration. The man's weight is M g = 735 N. For the man to decelerate at a rate a, the rope must apply a friction force F to the man such that

    M g - F = M a

    F is also the rope tension, which must not exceed 580 N.

    At maximum possible F (580 N), one gets the minimum possible acceleration, a_min

    a_min = g - 580/M = 9.8 - (580/75)
    = 2.1 m/s^2

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