Posted by ann on Thursday, January 12, 2012 at 10:22pm.
I assume the line is perpendicular to
the given line.
y-3 = 3(x+1).
y-3 = 3x+3,
-3x+y = 6,
3x-y = -6.
m1 = -A/B = -3/-1 = 3.
m2 = -1/3 = Negative reciprocal.
y = mx + b,
y = (-1/3)*5 + b = 1,
b = 1 + 5/3 = 2 2/3 = 8/3.
y = (-1/3)x+8/3,
Convert to STD form:
x/3 + y = 8/3,
X + 3Y = 8.
ADDITION: Let Y = 0 to find X-int.
X + 3Y = 8,
X + 3*0 = 8,
X = 8 = x-int.
thank you so much for your help Henry, I really appreciate it. Ann
I understand now where I went wrong. first mistake i made was using positive 1/3 and then it was downhill from there.
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