Sunday

December 21, 2014

December 21, 2014

Posted by **Casey** on Thursday, January 12, 2012 at 9:31pm.

Could someone explain this question to me, this isn't exactly the same as polynomial functions >.<

- Precalculus -
**Damon**, Thursday, January 12, 2012 at 9:46pmIt just says estimate so do that. add a small amount, say .1 to x and see how much f(x) changes

then the rate of change is (f(-3+.1) - f(3) )/.1

[f(-2.9) - f(3) ] / .1

= [-1.38 - (-1.5)]/.1

= .12/.1

= 1.2

- Precalculus -
**Damon**, Thursday, January 12, 2012 at 9:49pmNow if you knew calculus you would have said:

dy/dx = [(x+5)(1) - x(1) ] / (x+5)^2

= 5/(x+5)^2

at x = -3 that is

5/4 = 1.25 well not bad

- Precalculus -
**Casey**, Thursday, January 12, 2012 at 9:56pmWhat did you with -3/2? You have not used it, why?

- Precalculus -
**Damon**, Friday, January 13, 2012 at 7:39amWell, I used 1.5 instead of 3/2

**Answer this Question**

**Related Questions**

Math - Could someone help me with these questions, I don't know question c) and ...

Math~Reinyyy - Could someone help me with these questions, I don't know ...

Math:Polynomial Functions - h(x) = -7x I was thinking that this was not a ...

PreCalculus - I'm having trouble with these problems.. Could someone please ...

Advanced functions/precalculus - 1. Given f(x)=x^2 and g(x)=x+2, determine in ...

calculus - Can someone explain how find the average rate change for these ...

Graphs of polynomial functions - What do polynomial functions look like? And ...

Polynomial Functions-help - What do polynomial functions look like? And what can...

Polynomial Functions - What do polynomial functions look like? And what can be ...

advanced Functions/ Precalculus Log - 1. If (x, y) is on the graph f(x) = log(...