Posted by C. on Thursday, January 12, 2012 at 9:12pm.
Vx = 25 cos 50
Vyi = 25 sin 50 (the little i means initial)
Time in the air is determined entirely by the vertical problem.
It starts up with initial velocity Vyi = 25 sin 50
It slows down and stops at the top due to gravity
v = Vyi - g t = 0 at top
so
t at top = Vyi/g
time in air, multiply that by two. It takes as much time to fall as to rise.
Now athe horizontal problem
There is not horizontal force so no horizontal acceleration.
Thus the speed is constant and equal to Vx = 25 cos 50
for the time in air
so
C) answer is Vx * t in air
d) how high did it go in that original t seconds? (half the time in the air)
h = Vyi t - (1/2)g t^2
thank you so much!!!!!
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