a ball of mass 1oog falls from a height of 5m onto a floor and rebounds to a height of 3m . what energy is lost as a result of the impact on the floor ?

To calculate the energy lost during the impact on the floor, we need to determine the potential energy before and after the impact.

The potential energy of an object near the surface of the Earth is given by the formula:

Potential energy = mass x acceleration due to gravity x height

Given that the mass of the ball is 100g or 0.1kg, the height before the impact is 5m, and the height after the impact is 3m, we can calculate the potential energy before and after the impact.

Potential energy before the impact = 0.1kg x 9.8m/s^2 x 5m
Potential energy before the impact = 4.9 Joules

Potential energy after the impact = 0.1kg x 9.8m/s^2 x 3m
Potential energy after the impact = 2.94 Joules

The energy lost during the impact on the floor can be found by subtracting the potential energy after the impact from the potential energy before the impact.

Energy lost = Potential energy before the impact - Potential energy after the impact
Energy lost = 4.9 Joules - 2.94 Joules
Energy lost = 1.96 Joules

Therefore, the energy lost as a result of the impact on the floor is 1.96 Joules.

PE = mgh

since the final h is 60% of the initial h, 40% of the energy was lost.

For the actual amount, plug in the values.