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posted by Anonymous on Thursday, January 12, 2012 at 4:38pm.
Isosceles triangle ABC has vertices at A(0, 0), B(8, 0), and C(x, 12). The value of x could be
I guess AC = BC d^2 = x^2 + 144 = (x-8)^2 + 144 x^2 -16 x + 64 = x^2 x = 64/16 = 4
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