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Posted by **Kiersten Hailey** on Thursday, January 12, 2012 at 3:32pm.

PLEASE help!? /:

- Algebra 1 -
**Damon**, Thursday, January 12, 2012 at 3:38pmfirst boat goes for t + 2 min at 20/60

second boat goes for t min at 25/60

distance = same = speed * time

20(t+2)/60 = 25 t/60

4(t+2) = 5 t

8 minutes = t

- Algebra 1 -
**Kiersten Hailey**, Thursday, January 12, 2012 at 3:39pmThanks!! :)

- Algebra 1 -
**Steve**, Thursday, January 12, 2012 at 3:42pmdistance = speed * time

the second boat travels 2 min less than the first boat

converting mph to miles/min, both boats traveled for m minutes, making the same distance.

m * 20/60 = (m-2) * 25/60

20m = 25m - 50

5m = 50

m = 10

10 min at 20mph = 20 * 10/60 = 200/60mi

8 min at 25mph = 25 * 8/60 = 200/60 mi

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