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A garage lift has input and output circular pistons with diameters of 1 cm and 45 cm respectively. The lift is used to hold up a car with a weight of 1.7×103 N. What is the force on the input piston and what pressure is applied to the input piston

  • physics - ,

    1.7*10^3 (1^2/45^2) = .84 N

    .84/(pi 1^2) is pressure in Newtons/cm^2 in the fluid on both pistons.
    To convert to Pascals divide by 10^4 cm^2/m^2

    By the way, I think it is more likely that your car has a mass of 1.7 * 10^3 kg and a weight of 1.73*9.81 *10^3 = 1.7*10^4 N

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