A person invested $20,000 in stocks and bonds. Her investment in bonds is $4,000 more than one third her investment in stocks. How much did she invest in stocks? How much did she invest in bonds?

s + b = 20000

s + (4000 + s/3) = 20000
4/3 s = 16000
s = 12000
b = 8000

To find out how much the person invested in stocks and bonds, we can set up a system of equations.

Let's say the amount invested in stocks is "S" and the amount invested in bonds is "B."

From the given information, we know that the investment in bonds is $4,000 more than one-third of the investment in stocks. We can express this relationship as:

B = (1/3)S + $4,000

We also know that the total investment, which is the sum of the investments in stocks and bonds, is $20,000. Mathematically, this can be written as:

S + B = $20,000

Now we have a system of two equations:

B = (1/3)S + $4,000
S + B = $20,000

To solve this system of equations, we can use substitution or elimination. Let's use substitution to solve it.

Substitute the value of B from the first equation into the second equation:

S + (1/3)S + $4,000 = $20,000

Combine the like terms:

(4/3)S + $4,000 = $20,000

Subtract $4,000 from both sides:

(4/3)S = $16,000

To solve for S, we can multiply both sides by (3/4):

S = ($16,000) * (3/4)
S = $12,000

Therefore, the person invested $12,000 in stocks.

Now substitute this value back into the first equation to find the investment in bonds:

B = (1/3)S + $4,000
B = (1/3)($12,000) + $4,000
B = $4,000 + $4,000
B = $8,000

So, the person invested $12,000 in stocks and $8,000 in bonds.