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October 1, 2014

October 1, 2014

Posted by **HelpPlease** on Thursday, January 12, 2012 at 8:45am.

The width of a certain painting is 5cm less than twice the length. The length of the diagonal distance across the painting is 107cm. Find the length and width. Round your answer to 2 decimal places.

Can you check is my substitute is correct?

digonal distance: 107

width: 2L-5

length: L

a^2 + b^2 = c^2

(2L-5)^2 + L^2 = 107^2

please help and thank you

- Math -
**HelpPlease**, Thursday, January 12, 2012 at 8:56amnever mind found my other post!

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