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I need help on this math problem.

The width of a certain painting is 5cm less than twice the length. The length of the diagonal distance across the painting is 107cm. Find the length and width. Round your answer to 2 decimal places.

Can you check is my substitute is correct?

digonal distance: 107
width: 2L-5
length: L

a^2 + b^2 = c^2
(2L-5)^2 + L^2 = 107^2

please help and thank you

  • Math - ,

    never mind found my other post!

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