Posted by **Need Help** on Wednesday, January 11, 2012 at 10:06pm.

I need help on this math problem.

The width of a certain painting is 5cm less than twice the length. The length of the diagonal distance across the painting is 107cm. Find the length and width. Round your answer to 2 decimal places.

Substitute:

diagonal distance: 107cm

length: L

width: 2L-5

Is the substitutes correct?

Should I use the pythagoras method?

Can someone put me in the right track please so I can work out the problem?

please help and thank you

- Math 11 -
**Steve**, Thursday, January 12, 2012 at 6:08am
yes

yes

L^2 + (2L-5)^2 = 107^2

L^2 + 4L^2 - 20L + 25 = 11449

L = 49.84

- Math 11 -
**HelpPlease**, Thursday, January 12, 2012 at 9:38am
the next step is:

5L^2-20L=11424

right?

- Math 11 -
**Steve**, Thursday, January 12, 2012 at 10:44am
Almost. Set the equation to zero to solve:

5L^2-20L-11424 = 0

then use the quadratic formula to get L.

## Answer this Question

## Related Questions

- Math - I need help on this math problem. The width of a certain painting is 5cm...
- Math 11 - I need help on this math problem. The width of a certain painting is ...
- Algebra II - I have a question about Algebra polynomials. Question goes about ...
- Math - A square mirror has sides measuring 2 ft. less than the sides of a square...
- Math Geometry - Marisol is painting on a piece of canvas that has an area of ...
- Math - Another painting has length : width ratio approximately equal to the ...
- Math Geometry - Marisol is painting on a piece of canvas that has an area of ...
- Math - An artist wants to frame a square painting with an area of 400 square ...
- Math. fast please! - The length of a rectangle is 3 cm and the width is 2 cm. ...
- Math - a square painting is surrounded by a 2.5cm frame. if the total are of the...

More Related Questions