Thursday
August 21, 2014

Homework Help: Math 11

Posted by Need Help on Wednesday, January 11, 2012 at 10:06pm.

I need help on this math problem.

The width of a certain painting is 5cm less than twice the length. The length of the diagonal distance across the painting is 107cm. Find the length and width. Round your answer to 2 decimal places.

Substitute:
diagonal distance: 107cm
length: L
width: 2L-5

Is the substitutes correct?
Should I use the pythagoras method?
Can someone put me in the right track please so I can work out the problem?

please help and thank you

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Math - I need help on this math problem. The width of a certain painting is 5cm...
Math 11 - I need help on this math problem. The width of a certain painting is ...
Math. fast please! - The length of a rectangle is 3 cm and the width is 2 cm. ...
Math - A square mirror has sides measuring 2 ft. less than the sides of a square...
math - the length of a rectangular playing field is 5ft less than twice its ...
math - the length of a rectangle is 1 cm less than twice its width. the area is ...
alg 150 help - the width of a rectangle is 9 less than twice the length. if the ...
math - what would the dimensions of a retangle be whose perimeter is 50(P=50)...
College Math II - Write a complete solution to each problem. If the length of a ...
math - the length of a rectangle is 1 inch less than twice the width, and the ...

Search
Members