If we add 25g oe calcium carbonat with 73g of Hcl.what is the volume carbon dixiode in litres.
This is a limiting reagent problem. I know that because amounts are given for BOTH reactants.
1. Write and balance the equation.
2a. Convert 25 g CaCO3 to mol. mol = grams/molar mass.
2b. Convert 73 g HCl to moles.
3a. Using the coefficients in the balanced equation, convert mol CaCO3 to mol CO2.
3b. Same procedure, convert mol HCl to mol CO2.
3c. The answers for 3a and 3b will be different; obviously both answers can't be correct. The correct answer in limiting reagent problems is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
4. Using the smaller value, convert mol CO2 to L. mol x 22.4L/mol = ?L