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October 25, 2014

October 25, 2014

Posted by **Anonymous** on Wednesday, January 11, 2012 at 9:11pm.

- physics -
**Steve**, Thursday, January 12, 2012 at 10:35amI assume by 107 you mean 10^7, so the satellite is at an altitude of 31000 km.

If we ignore the curvature of the earth, and consider it a plane, then we have an isosceles triangle of height 3.1x10^7m, and a base of 3.1x10^6m, similar to a triangle of base 1, height 10. So, the distance traveled is 3.1x10^6 * sqrt(101) * 2 = 62.3x10^6m.

The speed of light is 3.0x10^8m/s

so, the call takes 6.23x10^7/3.0x10^8 = 2.07x10^-1 = 0.207s.

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