Posted by Sara on Wednesday, January 11, 2012 at 7:30pm.
solve the logarithm equation show work.
log_7(x8) log_7(x2)=1

precalculus  Damon, Wednesday, January 11, 2012 at 7:39pm
log7 [(x8)/(x2)] = 1
[(x8)/(x2)] = 7*1 = 7
x  8 = 7 x  14
6 x = 6
x = 1