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January 20, 2017
Posted by **Sara** on Wednesday, January 11, 2012 at 7:28pm.

ln(x-7/x^2+12x+36)-ln(x^2-49/x+6)

- precalculus -
**Damon**, Wednesday, January 11, 2012 at 7:35pmfirst

x^2+12x+36 = (x+6)(x+6)

so

ln of

(x-7)(x+6)

=====================

(x+6)(x+6)(x+7)(x-7)

ln of

1

=====================

(x+6)(x+1)

= ln 1 - ln(x^2 +7x + 6)

but ln 1 = 0

so

- ln (x^2 + 7 x + 6)