precalculus
posted by Sara on .
write the expression below as a single logarithm show work.
ln(x7/x^2+12x+36)ln(x^249/x+6)

first
x^2+12x+36 = (x+6)(x+6)
so
ln of
(x7)(x+6)
=====================
(x+6)(x+6)(x+7)(x7)
ln of
1
=====================
(x+6)(x+1)
= ln 1  ln(x^2 +7x + 6)
but ln 1 = 0
so
 ln (x^2 + 7 x + 6)