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March 31, 2015

March 31, 2015

Posted by **Rose** on Wednesday, January 11, 2012 at 5:58pm.

- Algebra 1 -
**Steve**, Thursday, January 12, 2012 at 12:07amLet a = no. of singles titles

Let b = no. of women's doubles titles

Let c = no. of mixed doubles titles

a + b + c = 60

a = c+8

b = 2 + 3c

c+8 + 2+3c + c = 60

5c + 10 = 60

5c=50

c=10

so,

a = 18

b = 32

so,

18 = no. of singles titles

32 = no. of women's doubles titles

10 = no. of mixed doubles titles

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