You are driving your car and the traffic light ahead turns red. you apply the breaks for 3.0 s, and the velocity of the care decrease for +4.5 m/s. if the cars deceleration has a magnitude of 2.7 m/s^2, what is the cars displacement during this time?
Your statement " the velocity of the care decrease for +4.5 m/s. " does not make sense. You have already said the time interval of deceleration is 3.0 s. Please type the question more carefully.
To find the displacement of the car during this time, we can use the equation of motion:
v^2 = u^2 + 2as
Where:
v = final velocity (0 m/s, as the car comes to a stop)
u = initial velocity (4.5 m/s in the positive direction)
a = acceleration (deceleration in this case, -2.7 m/s^2)
s = displacement
We know the initial velocity, final velocity, and acceleration, so we can rearrange the equation to solve for displacement:
s = (v^2 - u^2) / (2a)
Substituting the given values:
s = (0^2 - 4.5^2) / (2 × -2.7)
s = (-20.25) / (-5.4)
s = 3.75 meters
Therefore, the car's displacement during this time is 3.75 meters.