Posted by **INTEGRAL** on Tuesday, January 10, 2012 at 11:10pm.

Please help..

ʃ (4sin²x cos²×/sin 2x cos 2x)dx

That's integration of (4sin^2x cos^2x over sin 2x cos 2x) dx

i've got it from the back and it has an answer from the back page of the book but i want to know how to solve it..i really need it for practicing this subject...please please help..Thanks a lot..

the answer is: -1/2 ln|secx + tanx| + c

- CALCULUS -
**Mgraph**, Tuesday, January 10, 2012 at 11:24pm
4sin^2(x)cos^2(x)=(sin2x)^2

(sin2x/cos2x)dx=(-1/2)d(cos2x)/cos2x

- CALCULUS -
**Steve**, Wednesday, January 11, 2012 at 4:36pm
Hmm. There's something wrong here. Mgraph's solution is correct, but is not what you were expecting.

ln|secx + tanx| is the integral of secx, not sinx/cosx

Is there a typo somewhere?

## Answer This Question

## Related Questions

- TRIG! - Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6...
- Mathematics - Trigonometric Identities - Let y represent theta Prove: 1 + 1/tan^...
- Math - Calculus - The identity below is significant because it relates 3 ...
- tigonometry - expres the following as sums and differences of sines or cosines ...
- algebra - Can someone please help me do this problem? That would be great! ...
- trig - Reduce the following to the sine or cosine of one angle: (i) sin145*cos75...
- calculus - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x...
- trig - I dont understand this. can you please tell how you got each answer? ...
- Calculus 12th grade (double check my work please) - 1.)Find dy/dx when y= Ln (...
- Trig - Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < ...

More Related Questions