Posted by INTEGRAL on Tuesday, January 10, 2012 at 11:10pm.
Please help..
ʃ (4sin²x cos²×/sin 2x cos 2x)dx
That's integration of (4sin^2x cos^2x over sin 2x cos 2x) dx
i've got it from the back and it has an answer from the back page of the book but i want to know how to solve it..i really need it for practicing this subject...please please help..Thanks a lot..
the answer is: 1/2 lnsecx + tanx + c

CALCULUS  Mgraph, Tuesday, January 10, 2012 at 11:24pm
4sin^2(x)cos^2(x)=(sin2x)^2
(sin2x/cos2x)dx=(1/2)d(cos2x)/cos2x

CALCULUS  Steve, Wednesday, January 11, 2012 at 4:36pm
Hmm. There's something wrong here. Mgraph's solution is correct, but is not what you were expecting.
lnsecx + tanx is the integral of secx, not sinx/cosx
Is there a typo somewhere?
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