Posted by **Susan** on Tuesday, January 10, 2012 at 10:26pm.

A daredevil decides to jump a canyon of width 10 m. To do so, he drives a motorcycle up an incline sloped at an angle of 15 degrees. What minimum speed must he have in order to clear the canyon?

- Physics -
**Steve**, Wednesday, January 11, 2012 at 4:19pm
Assuming the motorcycle acts like a point mass (we don't want him to make it across with just his front wheel!) just drag out your good old equations for a trajectory:

for initial velocity v at angle t, the range is

r = (v^2 sin 2t)/g

10 = (v^2 sin 30°)/9.8

v^2 = 20 * 9.8 = 196

v = 14m/s or 50.4 km/hr

Just to check:

he'll be in the air 10/14 = .71 sec

his vertical velocity starts at 14 sin 15° = 3.62m/s

v = 3.62 - 9.8t

when v=0 (top of the arc) t = .36 sec

just about right. He has to go up and then come back down, taking .72 sec in all.

- Physics -
**]68p6**, Friday, December 6, 2013 at 4:08pm
nhkmlu5te

- Physics -
**Eddie**, Friday, December 6, 2013 at 4:09pm
14m/s

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