Monday

October 20, 2014

October 20, 2014

Posted by **aze** on Tuesday, January 10, 2012 at 9:54pm.

B) IS THE PARTICLE MOVING CLOCKWISE OR COUNTERCLOCKWISE AROUND THE CIRCLE

C) FROM THE RT TRIANGLE ONE CAN SEE THAT SIN(THETA) = Y AND COS(THETA) = X

USE THESE RELATIONS TO SHOW THAT THE ANGLE THETA IS CHANGING AT A CONST. RATE AND THEN FIND THAT RATE

- calculus -
**Mgraph**, Tuesday, January 10, 2012 at 11:55pmB)CLOCKWISE

In 1st quadrant (for ex.)dx/dt>0, so

x increases;

C)dx/dt=d(cos(theta))/dt=

d(cos(theta))/d(theta)*d(theta)/dt=

-sin(theta)*d(theta)/dx, so

dx/dt=-y*d(theta)/dt =>d(theta)/dt=-1

**Answer this Question**

**Related Questions**

calculus - A. a particle moves around the circle x^2+y^2 = 1 in such a way that ...

Calc - A particle moves along the x-axis in such a way that it's position in ...

Calc - A particle moves along the x-axis in such a way that it's position in ...

DIFF. CALCULUS - A particle is moving along the parabola 4y = (x + 2)^2 in such ...

CALCULUS BC - a particle moves on the x-axis in such a way that its position at ...

Calculus, Related Rates - A particle at point A is 50 mm away from a second ...

Calculus - A particle is moving along the curve . As the particle passes through...

Calculus - A particle is moving along the curve . As the particle passes through...

Calculus - A particle is moving along the curve . As the particle passes through...

calculus - A particle is moving along the curve y=4((3x+1)^.5). As the particle ...