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November 29, 2014

November 29, 2014

Posted by **aze** on Tuesday, January 10, 2012 at 9:54pm.

B) IS THE PARTICLE MOVING CLOCKWISE OR COUNTERCLOCKWISE AROUND THE CIRCLE

C) FROM THE RT TRIANGLE ONE CAN SEE THAT SIN(THETA) = Y AND COS(THETA) = X

USE THESE RELATIONS TO SHOW THAT THE ANGLE THETA IS CHANGING AT A CONST. RATE AND THEN FIND THAT RATE

- calculus -
**Mgraph**, Tuesday, January 10, 2012 at 11:55pmB)CLOCKWISE

In 1st quadrant (for ex.)dx/dt>0, so

x increases;

C)dx/dt=d(cos(theta))/dt=

d(cos(theta))/d(theta)*d(theta)/dt=

-sin(theta)*d(theta)/dx, so

dx/dt=-y*d(theta)/dt =>d(theta)/dt=-1

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