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March 30, 2015

March 30, 2015

Posted by **frank** on Tuesday, January 10, 2012 at 9:39pm.

- physics -
**MEOW**, Wednesday, January 11, 2012 at 3:03amMake your coordinate system so that tension is positive for the object with the given mass and negative for the object with the unknown. So the x component for the first weight is going to be w1*cos(theta). We are not given the angle so we can rewrite this as n1/w1. This can be done similarly with the second weight which turn out to be n2/w2.

So now the summation across the x components must equal 0, since it is in equilibrium. So:

Tension-n1/w1 = 0, for the first block.

-Tension+n2/w = 0, for the second block.

Tension==n1/w1==n2/w2, since the tension will be the same for both block since pulleys change the direction of the force, not the magnitude.

Notice that gravity will cancel out so that we are only left with mass: Let mass2==n3;

n1/(48Kg*g)=n2*(n3*g), solve for n3.

n3=n2*48kg/n1.

Just plug the respective values for n2 and n1 and you won't get "OPPS Try Again"

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