Sunday

December 21, 2014

December 21, 2014

Posted by **Anon** on Tuesday, January 10, 2012 at 9:22pm.

1. Find the solution set for x^2/(x+3) < 9/(x+3).

x^2/(x+3) < 9/(x+3)

x^2 < 9

x^2 - 9 < 0

(x-3)(x+3)<0

- Precalculus -
**Anonymous**, Tuesday, January 10, 2012 at 11:02pmx ^ 2 / ( x + 3 ) < 9 /( x + 3 ) Multiply both sides with ( x + 3 )

x ^ 2 < 9

x < + OR - 3

For :

x = - 3

x + 3 = 0

and

x ^ 2 / ( x + 3 ) = infinity

For that reason solution is x < 3

**Answer this Question**

**Related Questions**

Precalculus - Calculate solution set. x^2+4y^2=68 xy=8

math show work please - 1-11/x+30/x^2=0 A.the solution set is ? B.The solution ...

precalculus - Find all solutions of the system of equations. (If there is no ...

math show work please - 1/(X+3)+4/(x+5)= 2/(x^2+8x+15) a. the solution set is b...

Precalculus - I know I posted this already but.. I don't understand what ...

Precalculus(NEED HELP ASAP PLEASE!!) - Solve: sin(theta)+cos(theta) = 1 0 < ...

calculus - solve the following inequality 15x-16 less than or equal to 15/x is ...

Precalculus - Solve for the equation in the given domain. (tan theta)(sec theta...

St josephs - Machine set up is correct 60% of time & is incorrect 40% of time, ...

chemistry - how do you find the mass solute(g), GFM(g/mole), moles of solute, ...