Homework Help: Precalculus

Posted by Anon on Tuesday, January 10, 2012 at 9:22pm.

Is this correct?

1. Find the solution set for x^2/(x+3) < 9/(x+3).

x^2/(x+3) < 9/(x+3)

x^2 < 9
x^2 - 9 < 0

(x-3)(x+3)<0

Precalculus - Anonymous, Tuesday, January 10, 2012 at 11:02pm
x ^ 2 / ( x + 3 ) < 9 /( x + 3 ) Multiply both sides with ( x + 3 )

x ^ 2 < 9

x < + OR - 3

For :

x = - 3

x + 3 = 0

and

x ^ 2 / ( x + 3 ) = infinity

For that reason solution is x < 3

Answer this Question

Related Questions

algebra3 - Why isn't the absolute value inequality (x^2-1)</=8 set up...
Precalculus - 1. Determine the interval(s) on which x^2 + 2x -3>0 a)x&...
math - I think this question has a typo because none of the multiple choice ...
Precalculus - Help with these questions help with these questions~ Thank you 1. ...
Trignometry - Given Triangle ABC: I think there are suppose to be right ...
Trigonometry - Given Triangle ABC: Right Triangles 1. If a = 6 and <B = ...
Math - Solve the compound inequality -1 < X - 2 LESS THAN OR EQUAL TO 7 ...
Probability - A random variable N has a cumulative distribution function given ...
Probability - A random variable N has a cumulative distribution function given ...
Probability - A random variable N has a cumulative distribution function given ...

For Further Reading

First Name:
School Subject:
Answer: