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February 27, 2015

February 27, 2015

Posted by **corinne** on Tuesday, January 10, 2012 at 9:13pm.

1. y=(lnx)^3

2. y=x^4lnx

3. y=sin^3(lnx)

- calculus -
**Steve**, Wednesday, January 11, 2012 at 12:12am1. use chain rule

u = lnx

y = u^3

dy/dx = 3u^2 du/dx = 3(lnx)^2/x

2. use product rule

f=x^4

g=lnx

y = fg

y' = f'g + fg' = 4x^3 lnx + x^4/x = x^3(4lnx + 1)

3. use chain rule

u = lnx

v = sin(u)

y = v^3

dy/dx = dy/dv dv/du du/dx

= 3v^2 * cos(u) * 1/x

= 3sin^2(lnx) * cos(lnx) * 1/x

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