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April 19, 2014

April 19, 2014

Posted by **Jake** on Tuesday, January 10, 2012 at 4:31pm.

Thanky you!

1.What is the range of the reciprocal function of f(x)=10-x^2?

a) {YER|y≥1/10}

b) {YER|y≥10}

c) {YER|1/10≤y<0}

d) YER|y<0 or y≥1/10}

Answer: D?

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2. It takes Franc 2 hours longer than jane to carpet a certain type of room. Together they can carpet that type of room in 1 7/8 hours. How long would it take for Frank to do the job alone?

a) 1 1/4 hours

b) 3 3/4 hours

c) 3 hours

d) 5 hours

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4. Solve 4x/x-2 = 3x-2/x-2 for x.

a) x= -1/2

b) x= -2, 2

c) x= -2

d) x=2

Answer: B

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5. How many solutions does this equation (x+5)/(x-3)-1/x = 4/(x^2-3x) have?

a) 0

b) 1

c) 2

d) 3

Answer: C

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6. The inequality 3x-2<(x+4)/(x-2) is equivalent to which of the following?

a) 3x^2 - 9x + 8<0

b) (3x^2-9x+8)/(x-2)<0

c) 3x^2-9x>0

d) (3x^2 - 9x)/(x-2)<0

Answer: D

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- Precalculus -
**Steve**, Tuesday, January 10, 2012 at 5:39pm1.

y = 10 - x^2

x = sqrt(10-y)

domain: y <= 10

I don't see that as a choice.

2.

1/f + 1/j = 15/8

but f = j+2

1/(j+2) + 1/j = 15/8

8(j + j+2) = 15j(j+2)

16j + 16 = 15j^2 + 30j

15j^2 + 14j - 16 = 0

(3j-2)(5j+8) = 0

j = 2/3

so, f = 2 2/3

I don't see that as a choice.

4.

The answer is C, not B because 1/(x-2) is not defined.

5. C correct

6. D correct

- Precalculus -
**Jake**, Tuesday, January 10, 2012 at 5:46pmFor number 4, I got this answer after calculating...

4x/(x-2)=(3x-2)/(x-2)

4x(x-2)=(3x-2)(x-2)

4x^2 - 8x = 3x^2 - 6x - 2x + 4

4x^2-3x^2-8x+6x+2x-4=0

x^2 - 4 =0

(x-2)(x+2)=0

x= 2, -2

Am I doing something wrong?

- Precalculus -
**Steve**, Tuesday, January 10, 2012 at 11:34pmYes. 2 is not allowed as a solution, since putting it into the original equation gives

4x/(x-2)=(3x-2)/(x-2)

48/0 = 10/0

- Precalculus - PS -
**Steve**, Tuesday, January 10, 2012 at 11:34pmmake that

4/0 = 10/0

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