Posted by **amirah** on Tuesday, January 10, 2012 at 2:16pm.

A 1.4-kg block slides across a rough surface such that it slows down with an accerleration of 1.2 m/s2. What is the coefficient of kinetic friction between the block and the surface?

- physics -
**Henry**, Tuesday, January 10, 2012 at 5:05pm
Wb = mg = 1.4 kg * 9.8 N./kg = 13.72 N.

= Weight of block.

Fb = 13.72 N. @ 0 Deg.

Fp = 13.72*sin(0) = 0 = Force parallel to surface.

Fv = 13.72*cos(0) = 13.72 = Force perpendicular to surface.

Fn = Fp-Fk = ma,

0-u*13.72 = 1.4*(-1.2 = -1.68,

-13.72u = -1.68,

u = 0.1224.

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