f(x)=the squareroot of (x^2-9) and
find the domain and range of f(g(x)) anf f(f(x))
math/calculus - Steve, Tuesday, January 10, 2012 at 3:33pm
domain of f is all reals
domain of g is all reals except x=4
f(g) = g^2 - 9 = 1/(x-4)^2 - 9
domain of f(g) is the domain of g
range is all reals > -9
f(f) = f^2 - 9 = (x^2-9)^2 - 9
domain and range are all reals.
I expect you meant to type g(f(x)), but I'll let you do that as penalty...