Posted by **sandra** on Tuesday, January 10, 2012 at 11:52am.

A hiker travels N 33 degrees W for 15km, then turns 90 degrees and walks 12km in the direction S 57 degrees W At that time how far is the hiker from his starting point? What is his bearing from his starting point?

- math -
**Steve**, Tuesday, January 10, 2012 at 12:29pm
As usual, draw a diagram.

the distance is easy, since we have a right triangle

d^2 = 15^2 + 12^2 = 369

d = 19.2

The bearing is N (33+x) W where

tan x = 12/15

x = 37°

bearing is N 70° W

Alternatively, and with much more work,

(0,0) + (15 cos 123°,15 sin 123°) = (-8.17,12.58)

(-8.17,12.58) + (12 cos 213°, 12 sin213°) = (-8.17,12.58) + (-10.06,-6.54) = (-18.23,6.04)

d^2 = 369

tan x = -18.23/6.04 = -3.02

x = 180-20 = 160° = N 70° W

- math - oops -
**Steve**, Tuesday, January 10, 2012 at 12:29pm
oops

tan x = 6.04/-18.23

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