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September 18, 2014

September 18, 2014

Posted by **lisa** on Tuesday, January 10, 2012 at 12:25am.

Assume you want to estimate with the proportion of students who commute less than 5 miles to work within 2%, what sample size would you need?

- statistics -
**lisa**, Tuesday, January 10, 2012 at 12:26amcould someone please help me ASAP?

- statistics -
**MathGuru**, Tuesday, January 10, 2012 at 4:23pmTry this formula:

n = [(z-value)^2 * p * q]/E^2

= [(1.96)^2 * .5 * .5]/.02^2

I'll let you finish.

Note: n = sample size needed; .5 for p and .5 for q are used if no value is stated in the problem. E = maximum error, which is .02 (2%) in the problem. Z-value is found using a z-table (for 95%, the value is 1.96).

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