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Joe stands on a bridge kicking stones into the water below. If he kicks a stone with a horizontal velocity of 2.60 m/s, and it lands in the water a horizontal distance of 8.10 m from where Joe is standing, what is the height of the bridge? Enter m as unit.

  • physics - ,

    Since the horizontal velocity component remains constant, the time to fall must be
    T = 8.1m/(2.6 m/s) = 3.12 s

    For the height H, solve the equation
    H = (g/2)*T^2

    I get 47.6 m

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