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Posted by on Monday, January 9, 2012 at 8:49pm.

A skier of mass 71.0 kg is pulled up a slope
by a motor-driven cable.
How much work is required to pull the skier
62.2 m up a 37.0 slope (assumed to be fric-
tionless) at a constant speed of 2.0 m/s? The
acceleration of gravity is 9.81 m/s2 .

  • Physics - , Tuesday, January 10, 2012 at 12:21pm

    Ws = mg = 71 kg * 9.81 N./kg = 696 N. =
    Weight of skier.

    Fs = 696 N. @ 37 Deg. = Force of skier.
    Fp = 696*sin37 = 419 N. = Force parallel to slope.

    Ff = 0 = Force of friction.

    Fn = Fap - Fp - Ff = 0. a = o.
    Fap-419-0 = 0,
    Fap = 419 N. = Force applied.

    h = 62.2*sin37 = 37.4 m.
    W = Fap*h = 419 * 37.4 = 15,684 Joules

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