# Math

posted by on .

Lyle wanted change for a \$100 bill. He wanted at least three \$20 bills, one \$10 bill, one \$5 bill and seven \$1 bills. What is the least number of bills Lyle could have received?

A. 18
B. 16
C. 17
D. 15

I don't get how to get the answer

• Math - ,

How do you get the answer?

• Math - ,

(3 * 20) + 10 + 5 + 7 = \$82 >> 12 bills

100 - 82 = 18

10 + 5 + 3 = 18

12 + 3 = 15

• Math - ,

So it's D?

• Math - ,

let's go with the minimums and see what we get
3 20's + 1 10 + 1 5 + 7 1's = \$82 ---> 12 bills
so we are short \$18
using the least number of bills, I can fill that with
\$10 + \$5 + 3(\$1) --> 5 bills

total bills = 17

• Math - ,

Sorry but I'm confused. Because they said its D but you said its C
I also don't get why the \$82 is \$12

• Math - Correction - ,

Reiny is right. I can't add. Of course, 12 + 5 = 17.

• Math - ,

We need 12 bills to fulfill the minimum requirement.
That totals \$82 (check both Ms Sue's and mine)

leaving us \$18 short

the minimum way to get \$18 is
one ten
one five
3 ones , for a total of 5 more bills

total = 17

BTW, nowhere was it said that \$82 is \$12.