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September 21, 2014

September 21, 2014

Posted by **Anonymous** on Monday, January 9, 2012 at 5:00pm.

Find the distance traveled in 45 seconds by an object traveling at a velocity of v(t) = 20 + 3cos(t) feet per second. (Round your answer to the nearest foot.)

- Please Help!!!!!! -
**bobpursley**, Monday, January 9, 2012 at 5:16pmdistance=INTEGRAL velocity*dtime

- Please Help!!!!!! -
**Damon**, Monday, January 9, 2012 at 5:38pmIn cos t I assume t is in degrees. If you mean radians, then do it that way.

It is a calculus problem because every little bit of distance is v(t) times a tiny bit of time, delta t. It v(t) were constant you could just multiply v times change in time to get the answer, but v is not constant.

A primitive way to do this is to split the 45 seconds up into three 15 second periods. Approximate that it goes v(0) for the first 15, then v(15) for the second 15 (15 to 30), then v(30 for the last 15 (30 to 45)

v(0)(15) = 23 * 15 = 345

v(15) * 15 = 22.89 * 15 = 343.5

v(30) * 15 = 22.6 * 15 = 339

so

d = 1027.5

Next divide it into 5 spaces of 9 seconds each and see how much the answer changes.

- Please Help!!!!!! -
**Damon**, Monday, January 9, 2012 at 5:41pmI suspect that is not allowed Bob :) Too easy.

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